Solve 21/3+31/4-1=

$$2 \frac { 1 } { 3 } + 3 \frac { 1 } { 4 } - 1 =$$

Evaluate

$$\frac{55}{12}\approx 4.583333333$$

Solution Steps

Multiply 2 and 3 to get 6.

$$\frac{6+1}{3}+\frac{3\times 4+1}{4}-1$$

Add 6 and 1 to get 7.

$$\frac{7}{3}+\frac{3\times 4+1}{4}-1$$

Multiply 3 and 4 to get 12.

$$\frac{7}{3}+\frac{12+1}{4}-1$$

Add 12 and 1 to get 13.

$$\frac{7}{3}+\frac{13}{4}-1$$

Least common multiple of 3 and 4 is 12. Convert \frac{7}{3} and \frac{13}{4} to fractions with denominator 12.

$$\frac{28}{12}+\frac{39}{12}-1$$

Since \frac{28}{12} and \frac{39}{12} have the same denominator, add them by adding their numerators.

$$\frac{28+39}{12}-1$$

Add 28 and 39 to get 67.

$$\frac{67}{12}-1$$

Convert 1 to fraction \frac{12}{12}.

$$\frac{67}{12}-\frac{12}{12}$$

Since \frac{67}{12} and \frac{12}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{67-12}{12}$$

Subtract 12 from 67 to get 55.

$$\frac{55}{12}$$

Factor

$$\frac{5 \cdot 11}{2 ^ {2} \cdot 3} = 4\frac{7}{12} = 4.583333333333333$$