Solve 21/20+6(2^2+3^8)-4^2=

$$2 \frac { 1 } { 2 } 0 + 6 ( 2 ^ { 2 } + 3 ^ { 8 } ) - 4 ^ { 2 } =$$

Evaluate

$$39374$$

Solution Steps

Multiply 2 and 2 to get 4.

$$\frac{4+1}{2}\times 0+6\left(2^{2}+3^{8}\right)-4^{2}$$

Add 4 and 1 to get 5.

$$\frac{5}{2}\times 0+6\left(2^{2}+3^{8}\right)-4^{2}$$

Multiply \frac{5}{2} and 0 to get 0.

$$0+6\left(2^{2}+3^{8}\right)-4^{2}$$

Calculate 2 to the power of 2 and get 4.

$$0+6\left(4+3^{8}\right)-4^{2}$$

Calculate 3 to the power of 8 and get 6561.

$$0+6\left(4+6561\right)-4^{2}$$

Add 4 and 6561 to get 6565.

$$0+6\times 6565-4^{2}$$

Multiply 6 and 6565 to get 39390.

$$0+39390-4^{2}$$

Add 0 and 39390 to get 39390.

$$39390-4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$39390-16$$

Subtract 16 from 39390 to get 39374.

$$39374$$

Factor

$$2\times 19687$$