Solve 21/2+3+41/3

$$2 \frac { 1 } { 2 } + 3 + 4 \frac { 1 } { 3 }$$

Evaluate

$$\frac{59}{6}\approx 9.833333333$$

Solution Steps

Multiply 2 and 2 to get 4.

$$\frac{4+1}{2}+3+\frac{4\times 3+1}{3}$$

Add 4 and 1 to get 5.

$$\frac{5}{2}+3+\frac{4\times 3+1}{3}$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{5}{2}+\frac{6}{2}+\frac{4\times 3+1}{3}$$

Since \frac{5}{2} and \frac{6}{2} have the same denominator, add them by adding their numerators.

$$\frac{5+6}{2}+\frac{4\times 3+1}{3}$$

Add 5 and 6 to get 11.

$$\frac{11}{2}+\frac{4\times 3+1}{3}$$

Multiply 4 and 3 to get 12.

$$\frac{11}{2}+\frac{12+1}{3}$$

Add 12 and 1 to get 13.

$$\frac{11}{2}+\frac{13}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{11}{2} and \frac{13}{3} to fractions with denominator 6.

$$\frac{33}{6}+\frac{26}{6}$$

Since \frac{33}{6} and \frac{26}{6} have the same denominator, add them by adding their numerators.

$$\frac{33+26}{6}$$

Add 33 and 26 to get 59.

$$\frac{59}{6}$$

Factor

$$\frac{59}{2 \cdot 3} = 9\frac{5}{6} = 9.833333333333334$$