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\frac{26+1}{13}\left(\frac{1}{5}-\frac{1}{12}\right)-\frac{7}{\frac{3\times 2+1}{2}}
Multiply 2 and 13 to get 26.
\frac{27}{13}\left(\frac{1}{5}-\frac{1}{12}\right)-\frac{7}{\frac{3\times 2+1}{2}}
Add 26 and 1 to get 27.
\frac{27}{13}\left(\frac{12}{60}-\frac{5}{60}\right)-\frac{7}{\frac{3\times 2+1}{2}}
Least common multiple of 5 and 12 is 60. Convert \frac{1}{5} and \frac{1}{12} to fractions with denominator 60.
\frac{27}{13}\times \frac{12-5}{60}-\frac{7}{\frac{3\times 2+1}{2}}
Since \frac{12}{60} and \frac{5}{60} have the same denominator, subtract them by subtracting their numerators.
\frac{27}{13}\times \frac{7}{60}-\frac{7}{\frac{3\times 2+1}{2}}
Subtract 5 from 12 to get 7.
\frac{27\times 7}{13\times 60}-\frac{7}{\frac{3\times 2+1}{2}}
Multiply \frac{27}{13} times \frac{7}{60} by multiplying numerator times numerator and denominator times denominator.
\frac{189}{780}-\frac{7}{\frac{3\times 2+1}{2}}
Do the multiplications in the fraction \frac{27\times 7}{13\times 60}.
\frac{63}{260}-\frac{7}{\frac{3\times 2+1}{2}}
Reduce the fraction \frac{189}{780} to lowest terms by extracting and canceling out 3.
\frac{63}{260}-\frac{7\times 2}{3\times 2+1}
Divide 7 by \frac{3\times 2+1}{2} by multiplying 7 by the reciprocal of \frac{3\times 2+1}{2}.
\frac{63}{260}-\frac{14}{3\times 2+1}
Multiply 7 and 2 to get 14.
\frac{63}{260}-\frac{14}{6+1}
Multiply 3 and 2 to get 6.
\frac{63}{260}-\frac{14}{7}
Add 6 and 1 to get 7.
\frac{63}{260}-2
Divide 14 by 7 to get 2.
\frac{63}{260}-\frac{520}{260}
Convert 2 to fraction \frac{520}{260}.
\frac{63-520}{260}
Since \frac{63}{260} and \frac{520}{260} have the same denominator, subtract them by subtracting their numerators.
-\frac{457}{260}
Subtract 520 from 63 to get -457.