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\frac{\left(2\times 12+1\right)\times 4}{12\left(3\times 4+3\right)}
Divide \frac{2\times 12+1}{12} by \frac{3\times 4+3}{4} by multiplying \frac{2\times 12+1}{12} by the reciprocal of \frac{3\times 4+3}{4}.
\frac{1+2\times 12}{3\left(3+3\times 4\right)}
Cancel out 4 in both numerator and denominator.
\frac{1+24}{3\left(3+3\times 4\right)}
Multiply 2 and 12 to get 24.
\frac{25}{3\left(3+3\times 4\right)}
Add 1 and 24 to get 25.
\frac{25}{3\left(3+12\right)}
Multiply 3 and 4 to get 12.
\frac{25}{3\times 15}
Add 3 and 12 to get 15.
\frac{25}{45}
Multiply 3 and 15 to get 45.
\frac{5}{9}
Reduce the fraction \frac{25}{45} to lowest terms by extracting and canceling out 5.