Solve 2cos(60^circ)+-1+left|-3right|-{left(sqrt{2}-1right)}^0

$$2 \cos ( 60 ^ { \circ } ) +-1+ \left| -3 \right| - { \left( \sqrt{ 2 } -1 \right) }^{ 0 }$$

Evaluate

$$2$$

Solution Steps

Get the value of \cos(60) from trigonometric values table.

$$2\times \frac{1}{2}-1+|-3|-\left(\sqrt{2}-1\right)^{0}$$

Multiply 2 and \frac{1}{2} to get 1.

$$1-1+|-3|-\left(\sqrt{2}-1\right)^{0}$$

Subtract 1 from 1 to get 0.

$$|-3|-\left(\sqrt{2}-1\right)^{0}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$3-\left(\sqrt{2}-1\right)^{0}$$

Calculate \sqrt{2}-1 to the power of 0 and get 1.

$$3-1$$

Subtract 1 from 3 to get 2.

$$2$$