Solve for y
y=\frac{\sin(\pi x)}{2}
Solve for x (complex solution)
x=-\frac{i\ln(\sqrt{1-4y^{2}}+2iy)}{\pi }+2n_{1}\text{, }n_{1}\in \mathrm{Z}
x=-\frac{i\ln(-\sqrt{1-4y^{2}}+2iy)}{\pi }+2n_{2}\text{, }n_{2}\in \mathrm{Z}
Solve for x
x=\frac{\arcsin(2y)}{\pi }+2n_{1}\text{, }n_{1}\in \mathrm{Z}
x=\frac{-\arcsin(2y)+\pi }{\pi }+2n_{2}\text{, }n_{2}\in \mathrm{Z}\text{, }|y|\leq \frac{1}{2}
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2y=\sin(\pi x)
The equation is in standard form.
\frac{2y}{2}=\frac{\sin(\pi x)}{2}
Divide both sides by 2.
y=\frac{\sin(\pi x)}{2}
Dividing by 2 undoes the multiplication by 2.
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