Solve 2*x^{3}-3*x^{2}+4*x+7=9+5*x^3-4*x^2-3*x^3+x^2

$$2 \cdot x ^ { 3 } - 3 \cdot x ^ { 2 } + 4 \cdot x + 7 = 9 + 5 \cdot x ^ { 3 } - 4 \cdot x ^ { 2 } - 3 \cdot x ^ { 3 } + x ^ { 2 }$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Combine 5x^{3} and -3x^{3} to get 2x^{3}.

$$2x^{3}-3x^{2}+4x+7=9+2x^{3}-4x^{2}+x^{2}$$

Combine -4x^{2} and x^{2} to get -3x^{2}.

$$2x^{3}-3x^{2}+4x+7=9+2x^{3}-3x^{2}$$

Subtract 2x^{3} from both sides.

$$2x^{3}-3x^{2}+4x+7-2x^{3}=9-3x^{2}$$

Combine 2x^{3} and -2x^{3} to get 0.

$$-3x^{2}+4x+7=9-3x^{2}$$

Add 3x^{2} to both sides.

$$-3x^{2}+4x+7+3x^{2}=9$$

Combine -3x^{2} and 3x^{2} to get 0.

$$4x+7=9$$

Subtract 7 from both sides.

$$4x=9-7$$

Subtract 7 from 9 to get 2.

$$4x=2$$

Divide both sides by 4.

$$x=\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{1}{2}$$