Solve 2*m^2+1/3+2-2m-2/2

$$2 \cdot m ^ { 2 } + \frac { 1 } { 3 } + 2 - 2 m - \frac { 2 } { 2 }$$

Evaluate

$$2m^{2}-2m+\frac{4}{3}$$

Solution Steps

Divide 2 by 2 to get 1.

$$2m^{2}+\frac{1}{3}+2-2m-1$$

Add \frac{1}{3} and 2 to get \frac{7}{3}.

$$2m^{2}+\frac{7}{3}-2m-1$$

Subtract 1 from \frac{7}{3} to get \frac{4}{3}.

$$2m^{2}+\frac{4}{3}-2m$$

Factor

$$\frac{2\left(3m^{2}-3m+2\right)}{3}$$

Solution Steps

Factor out \frac{1}{3}.

$$\frac{6m^{2}+4-6m}{3}$$

Consider 6m^{2}+1+6-6m-3. Multiply and combine like terms.

$$6m^{2}-6m+4$$

Consider 6m^{2}-6m+4. Factor out 2.

$$2\left(3m^{2}-3m+2\right)$$

Rewrite the complete factored expression.

$$\frac{2\left(3m^{2}-3m+2\right)}{3}$$