Solve 2*3*4^5*4^5*6^-3

$$2 \cdot 3 \cdot 4 ^ { 5 } \cdot 4 ^ { 5 } \cdot 6 ^ { - 3 }$$

Evaluate

$$\frac{262144}{9}\approx 29127.111111111$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 5 and 5 to get 10.

$$2\times 3\times 4^{10}\times 6^{-3}$$

Multiply 2 and 3 to get 6.

$$6\times 4^{10}\times 6^{-3}$$

Calculate 4 to the power of 10 and get 1048576.

$$6\times 1048576\times 6^{-3}$$

Multiply 6 and 1048576 to get 6291456.

$$6291456\times 6^{-3}$$

Calculate 6 to the power of -3 and get \frac{1}{216}.

$$6291456\times \frac{1}{216}$$

Multiply 6291456 and \frac{1}{216} to get \frac{262144}{9}.

$$\frac{262144}{9}$$

Factor

$$\frac{2 ^ {18}}{3 ^ {2}} = 29127\frac{1}{9} = 29127.11111111111$$