Solve 2*(2*1+1)+18=3(1+2)(2*1+h)

$$2 \cdot ( 2 \cdot 1 + 1 ) + 18 = 3 ( 1 + 2 ) ( 2 \cdot 1 + h )$$

Solve for h

$$h=\frac{2}{3}\approx 0.666666667$$

Steps for Solving Linear Equation

Multiply 2 and 1 to get 2.

$$2\left(2+1\right)+18=3\left(1+2\right)\left(2\times 1+h\right)$$

Add 2 and 1 to get 3.

$$2\times 3+18=3\left(1+2\right)\left(2\times 1+h\right)$$

Multiply 2 and 3 to get 6.

$$6+18=3\left(1+2\right)\left(2\times 1+h\right)$$

Add 6 and 18 to get 24.

$$24=3\left(1+2\right)\left(2\times 1+h\right)$$

Add 1 and 2 to get 3.

$$24=3\times 3\left(2\times 1+h\right)$$

Multiply 3 and 3 to get 9.

$$24=9\left(2\times 1+h\right)$$

Multiply 2 and 1 to get 2.

$$24=9\left(2+h\right)$$

Use the distributive property to multiply 9 by 2+h.

$$24=18+9h$$

Swap sides so that all variable terms are on the left hand side.

$$18+9h=24$$

Subtract 18 from both sides.

$$9h=24-18$$

Subtract 18 from 24 to get 6.

$$9h=6$$

Divide both sides by 9.

$$h=\frac{6}{9}$$

Reduce the fraction \frac{6}{9} to lowest terms by extracting and canceling out 3.

$$h=\frac{2}{3}$$