Solve 2*(-16):y=9x-5

$$2 \cdot ( - 16 ) : y = 9 x - 5$$

Solve for x

$$x=\frac{5}{9}-\frac{32}{9y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by y.

$$2\left(-16\right)=9xy+y\left(-5\right)$$

Multiply 2 and -16 to get -32.

$$-32=9xy+y\left(-5\right)$$

Swap sides so that all variable terms are on the left hand side.

$$9xy+y\left(-5\right)=-32$$

Subtract y\left(-5\right) from both sides.

$$9xy=-32-y\left(-5\right)$$

Multiply -1 and -5 to get 5.

$$9xy=-32+5y$$

The equation is in standard form.

$$9yx=5y-32$$

Divide both sides by 9y.

$$\frac{9yx}{9y}=\frac{5y-32}{9y}$$

Dividing by 9y undoes the multiplication by 9y.

$$x=\frac{5y-32}{9y}$$

Divide 5y-32 by 9y.

$$x=\frac{5}{9}-\frac{32}{9y}$$

Solve for y

$$y=-\frac{32}{9x-5}$$

$$x\neq \frac{5}{9}$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$2\left(-16\right)=9xy+y\left(-5\right)$$

Multiply 2 and -16 to get -32.

$$-32=9xy+y\left(-5\right)$$

Swap sides so that all variable terms are on the left hand side.

$$9xy+y\left(-5\right)=-32$$

Combine all terms containing y.

$$\left(9x-5\right)y=-32$$

Divide both sides by -5+9x.

$$\frac{\left(9x-5\right)y}{9x-5}=-\frac{32}{9x-5}$$

Dividing by -5+9x undoes the multiplication by -5+9x.

$$y=-\frac{32}{9x-5}$$

Variable y cannot be equal to 0.

$$y=-\frac{32}{9x-5}\text{, }y\neq 0$$