Solve 2*(-1,6):y=9x-5

$$2 \cdot ( - 1,6 ) : y = 9 x - 5$$

Solve for x

$$x=\frac{5}{9}-\frac{16}{45y}$$

$$y\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by y.

$$2\left(-1,6\right)=9xy+y\left(-5\right)$$

Multiply 2 and -1,6 to get -3,2.

$$-3,2=9xy+y\left(-5\right)$$

Swap sides so that all variable terms are on the left hand side.

$$9xy+y\left(-5\right)=-3,2$$

Subtract y\left(-5\right) from both sides.

$$9xy=-3,2-y\left(-5\right)$$

Multiply -1 and -5 to get 5.

$$9xy=-3,2+5y$$

The equation is in standard form.

$$9yx=5y-3,2$$

Divide both sides by 9y.

$$\frac{9yx}{9y}=\frac{5y-3,2}{9y}$$

Dividing by 9y undoes the multiplication by 9y.

$$x=\frac{5y-3,2}{9y}$$

Divide 5y-3,2 by 9y.

$$x=\frac{5}{9}-\frac{16}{45y}$$

Solve for y

$$y=-\frac{16}{5\left(9x-5\right)}$$

$$x\neq \frac{5}{9}$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$2\left(-1,6\right)=9xy+y\left(-5\right)$$

Multiply 2 and -1,6 to get -3,2.

$$-3,2=9xy+y\left(-5\right)$$

Swap sides so that all variable terms are on the left hand side.

$$9xy+y\left(-5\right)=-3,2$$

Combine all terms containing y.

$$\left(9x-5\right)y=-3,2$$

Divide both sides by -5+9x.

$$\frac{\left(9x-5\right)y}{9x-5}=-\frac{3,2}{9x-5}$$

Dividing by -5+9x undoes the multiplication by -5+9x.

$$y=-\frac{3,2}{9x-5}$$

Divide -3,2 by -5+9x.

$$y=-\frac{16}{5\left(9x-5\right)}$$

Variable y cannot be equal to 0.

$$y=-\frac{16}{5\left(9x-5\right)}\text{, }y\neq 0$$