Solve 2*(2/5+2)-2*(1/2+5)

$$2 \cdot ( \frac { 2 } { 5 } + 2 ) - 2 \cdot ( \frac { 1 } { 2 } + 5 )$$

Evaluate

$$-\frac{31}{5}=-6.2$$

Solution Steps

Convert 2 to fraction \frac{10}{5}.

$$2\left(\frac{2}{5}+\frac{10}{5}\right)-2\left(\frac{1}{2}+5\right)$$

Since \frac{2}{5} and \frac{10}{5} have the same denominator, add them by adding their numerators.

$$2\times \frac{2+10}{5}-2\left(\frac{1}{2}+5\right)$$

Add 2 and 10 to get 12.

$$2\times \frac{12}{5}-2\left(\frac{1}{2}+5\right)$$

Express 2\times \frac{12}{5} as a single fraction.

$$\frac{2\times 12}{5}-2\left(\frac{1}{2}+5\right)$$

Multiply 2 and 12 to get 24.

$$\frac{24}{5}-2\left(\frac{1}{2}+5\right)$$

Convert 5 to fraction \frac{10}{2}.

$$\frac{24}{5}-2\left(\frac{1}{2}+\frac{10}{2}\right)$$

Since \frac{1}{2} and \frac{10}{2} have the same denominator, add them by adding their numerators.

$$\frac{24}{5}-2\times \frac{1+10}{2}$$

Add 1 and 10 to get 11.

$$\frac{24}{5}-2\times \frac{11}{2}$$

Cancel out 2 and 2.

$$\frac{24}{5}-11$$

Convert 11 to fraction \frac{55}{5}.

$$\frac{24}{5}-\frac{55}{5}$$

Since \frac{24}{5} and \frac{55}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-55}{5}$$

Subtract 55 from 24 to get -31.

$$-\frac{31}{5}$$

Factor

$$-\frac{31}{5} = -6\frac{1}{5} = -6.2$$