Solve 2*sqrt{27}-3*sqrt{12}=

$$2 \cdot \sqrt { 27 } - 3 \cdot \sqrt { 12 } =$$

Evaluate

$$0$$

Solution Steps

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$2\times 3\sqrt{3}-3\sqrt{12}$$

Multiply 2 and 3 to get 6.

$$6\sqrt{3}-3\sqrt{12}$$

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$6\sqrt{3}-3\times 2\sqrt{3}$$

Multiply -3 and 2 to get -6.

$$6\sqrt{3}-6\sqrt{3}$$

Combine 6\sqrt{3} and -6\sqrt{3} to get 0.

$$0$$

Factor

$$0$$