Solve 2*4x/3x-2=

$$2 \cdot \frac { 4 x } { 3 x - 2 } =$$

Evaluate

$$\frac{8x}{3x-2}$$

Solution Steps

Express 2\times \frac{4x}{3x-2} as a single fraction.

$$\frac{2\times 4x}{3x-2}$$

Multiply 2 and 4 to get 8.

$$\frac{8x}{3x-2}$$

Differentiate w.r.t. x

$$-\frac{16}{\left(3x-2\right)^{2}}$$

Steps Using Derivative Rule for Quotient

Express 2\times \frac{4x}{3x-2} as a single fraction.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{2\times 4x}{3x-2})$$

Multiply 2 and 4 to get 8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{8x}{3x-2})$$

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(3x^{1}-2\right)\frac{\mathrm{d}}{\mathrm{d}x}(8x^{1})-8x^{1}\frac{\mathrm{d}}{\mathrm{d}x}(3x^{1}-2)}{\left(3x^{1}-2\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(3x^{1}-2\right)\times 8x^{1-1}-8x^{1}\times 3x^{1-1}}{\left(3x^{1}-2\right)^{2}}$$

Do the arithmetic.

$$\frac{\left(3x^{1}-2\right)\times 8x^{0}-8x^{1}\times 3x^{0}}{\left(3x^{1}-2\right)^{2}}$$

Expand using distributive property.

$$\frac{3x^{1}\times 8x^{0}-2\times 8x^{0}-8x^{1}\times 3x^{0}}{\left(3x^{1}-2\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{3\times 8x^{1}-2\times 8x^{0}-8\times 3x^{1}}{\left(3x^{1}-2\right)^{2}}$$

Do the arithmetic.

$$\frac{24x^{1}-16x^{0}-24x^{1}}{\left(3x^{1}-2\right)^{2}}$$

Combine like terms.

$$\frac{\left(24-24\right)x^{1}-16x^{0}}{\left(3x^{1}-2\right)^{2}}$$

Subtract 24 from 24.

$$\frac{-16x^{0}}{\left(3x^{1}-2\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{-16x^{0}}{\left(3x-2\right)^{2}}$$

For any term t except 0, t^{0}=1.

$$\frac{-16}{\left(3x-2\right)^{2}}$$