Solve 2*5+2*6+2*4+2*3+2*1+2*4+2*3+2*2+2-6+2*12-40

$$2 \cdot 5+2 \cdot 6+2 \cdot 4+2 \cdot 3+2 \cdot 1+2 \cdot 4+2 \cdot 3+2 \cdot 2+2-6+2 \cdot 12-40$$

Evaluate

$$36$$

Solution Steps

Multiply 2 and 5 to get 10. Multiply 2 and 6 to get 12. Multiply 2 and 4 to get 8. Multiply 2 and 3 to get 6. Multiply 2 and 1 to get 2. Multiply 2 and 4 to get 8. Multiply 2 and 3 to get 6. Multiply 2 and 2 to get 4. Multiply 2 and 12 to get 24.

$$10+12+8+6+2+8+6+4+2-6+24-40$$

Add 10 and 12 to get 22.

$$22+8+6+2+8+6+4+2-6+24-40$$

Add 22 and 8 to get 30.

$$30+6+2+8+6+4+2-6+24-40$$

Add 30 and 6 to get 36.

$$36+2+8+6+4+2-6+24-40$$

Add 36 and 2 to get 38.

$$38+8+6+4+2-6+24-40$$

Add 38 and 8 to get 46.

$$46+6+4+2-6+24-40$$

Add 46 and 6 to get 52.

$$52+4+2-6+24-40$$

Add 52 and 4 to get 56.

$$56+2-6+24-40$$

Add 56 and 2 to get 58.

$$58-6+24-40$$

Subtract 6 from 58 to get 52.

$$52+24-40$$

Add 52 and 24 to get 76.

$$76-40$$

Subtract 40 from 76 to get 36.

$$36$$

Factor

$$2^{2}\times 3^{2}$$