Solve 2*2*2*2-9*x^2+12*2=4

$$2 \cdot 2 \cdot 2 \cdot 2-9 \cdot { x }^{ 2 } +12 \cdot 2 = 4$$

Solve for x

$$x=2$$

$$x=-2$$

Steps by Finding Square Root

Do the multiplications.

$$4\times 2\times 2-9x^{2}+24=4$$

Multiply 4 and 2 to get 8.

$$8\times 2-9x^{2}+24=4$$

Multiply 8 and 2 to get 16.

$$16-9x^{2}+24=4$$

Add 16 and 24 to get 40.

$$40-9x^{2}=4$$

Subtract 40 from both sides.

$$-9x^{2}=4-40$$

Subtract 40 from 4 to get -36.

$$-9x^{2}=-36$$

Divide both sides by -9.

$$x^{2}=\frac{-36}{-9}$$

Divide -36 by -9 to get 4.

$$x^{2}=4$$

Take the square root of both sides of the equation.

$$x=2 x=-2$$

Steps Using the Quadratic Formula

Do the multiplications.

$$4\times 2\times 2-9x^{2}+24=4$$

Multiply 4 and 2 to get 8.

$$8\times 2-9x^{2}+24=4$$

Multiply 8 and 2 to get 16.

$$16-9x^{2}+24=4$$

Add 16 and 24 to get 40.

$$40-9x^{2}=4$$

Subtract 4 from both sides.

$$40-9x^{2}-4=0$$

Subtract 4 from 40 to get 36.

$$36-9x^{2}=0$$

Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.

$$-9x^{2}+36=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -9 for a, 0 for b, and 36 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-9\right)\times 36}}{2\left(-9\right)}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-9\right)\times 36}}{2\left(-9\right)}$$

Multiply -4 times -9.

$$x=\frac{0±\sqrt{36\times 36}}{2\left(-9\right)}$$

Multiply 36 times 36.

$$x=\frac{0±\sqrt{1296}}{2\left(-9\right)}$$

Take the square root of 1296.

$$x=\frac{0±36}{2\left(-9\right)}$$

Multiply 2 times -9.

$$x=\frac{0±36}{-18}$$

Now solve the equation x=\frac{0±36}{-18} when ± is plus. Divide 36 by -18.

$$x=-2$$

Now solve the equation x=\frac{0±36}{-18} when ± is minus. Divide -36 by -18.

$$x=2$$

The equation is now solved.

$$x=-2 x=2$$