Solve 2^x-3=1/8

$$2 ^ { x - 3 } = \frac { 1 } { 8 }$$

Solve for x

$$x=0$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$2^{x-3}=\frac{1}{8}$$

Take the logarithm of both sides of the equation.

$$\log(2^{x-3})=\log(\frac{1}{8})$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$\left(x-3\right)\log(2)=\log(\frac{1}{8})$$

Divide both sides by \log(2).

$$x-3=\frac{\log(\frac{1}{8})}{\log(2)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x-3=\log_{2}\left(\frac{1}{8}\right)$$

Add 3 to both sides of the equation.

$$x=-3-\left(-3\right)$$

Solve for x (complex solution)

$$x=\frac{2\pi n_{1}i}{\ln(2)}$$

$$n_{1}\in \mathrm{Z}$$