Solve for x
x=-1
Solve for x (complex solution)
x=\frac{i\times 2\pi n_{1}}{\ln(2)}-1
n_{1}\in \mathrm{Z}
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2^{x+2}=2
Use the rules of exponents and logarithms to solve the equation.
\log(2^{x+2})=\log(2)
Take the logarithm of both sides of the equation.
\left(x+2\right)\log(2)=\log(2)
The logarithm of a number raised to a power is the power times the logarithm of the number.
x+2=\frac{\log(2)}{\log(2)}
Divide both sides by \log(2).
x+2=\log_{2}\left(2\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
x=1-2
Subtract 2 from both sides of the equation.
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