Solve 2^n=32

$$2 ^ { n } = 32$$

Solve for n

$$n=5$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$2^{n}=32$$

Take the logarithm of both sides of the equation.

$$\log(2^{n})=\log(32)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$n\log(2)=\log(32)$$

Divide both sides by \log(2).

$$n=\frac{\log(32)}{\log(2)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$n=\log_{2}\left(32\right)$$