Solve 2^{7}*2^2+5^4*5^3*2^4-3*2

$$2 ^ { 7 } \cdot 2 ^ { 2 } + 5 ^ { 4 } \cdot 5 ^ { 3 } \cdot 2 ^ { 4 } - 3 \cdot 2$$

Evaluate

$$1250506$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 7 and 2 to get 9.

$$2^{9}+5^{4}\times 5^{3}\times 2^{4}-3\times 2$$

To multiply powers of the same base, add their exponents. Add 4 and 3 to get 7.

$$2^{9}+5^{7}\times 2^{4}-3\times 2$$

Calculate 2 to the power of 9 and get 512.

$$512+5^{7}\times 2^{4}-3\times 2$$

Calculate 5 to the power of 7 and get 78125.

$$512+78125\times 2^{4}-3\times 2$$

Calculate 2 to the power of 4 and get 16.

$$512+78125\times 16-3\times 2$$

Multiply 78125 and 16 to get 1250000.

$$512+1250000-3\times 2$$

Add 512 and 1250000 to get 1250512.

$$1250512-3\times 2$$

Multiply 3 and 2 to get 6.

$$1250512-6$$

Subtract 6 from 1250512 to get 1250506.

$$1250506$$

Factor

$$2\times 625253$$