Solve 2^{6}+2^5+2^4+2^3+2^2+2+1

$$2 ^ { 6 } + 2 ^ { 5 } + 2 ^ { 4 } + 2 ^ { 3 } + 2 ^ { 2 } + 2 + 1$$

Evaluate

$$127$$

Solution Steps

Calculate 2 to the power of 6 and get 64.

$$64+2^{5}+2^{4}+2^{3}+2^{2}+2+1$$

Calculate 2 to the power of 5 and get 32.

$$64+32+2^{4}+2^{3}+2^{2}+2+1$$

Add 64 and 32 to get 96.

$$96+2^{4}+2^{3}+2^{2}+2+1$$

Calculate 2 to the power of 4 and get 16.

$$96+16+2^{3}+2^{2}+2+1$$

Add 96 and 16 to get 112.

$$112+2^{3}+2^{2}+2+1$$

Calculate 2 to the power of 3 and get 8.

$$112+8+2^{2}+2+1$$

Add 112 and 8 to get 120.

$$120+2^{2}+2+1$$

Calculate 2 to the power of 2 and get 4.

$$120+4+2+1$$

Add 120 and 4 to get 124.

$$124+2+1$$

Add 124 and 2 to get 126.

$$126+1$$

Add 126 and 1 to get 127.

$$127$$

Factor

$$127$$