Solve 2^5-20^2:(8^2-6*2^2)

$$2 ^ { 5 } - 20 ^ { 2 } : ( 8 ^ { 2 } - 6 \cdot 2 ^ { 2 } )$$

Evaluate

$$22$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$32-\frac{20^{2}}{8^{2}-6\times 2^{2}}$$

Calculate 20 to the power of 2 and get 400.

$$32-\frac{400}{8^{2}-6\times 2^{2}}$$

Calculate 8 to the power of 2 and get 64.

$$32-\frac{400}{64-6\times 2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$32-\frac{400}{64-6\times 4}$$

Multiply 6 and 4 to get 24.

$$32-\frac{400}{64-24}$$

Subtract 24 from 64 to get 40.

$$32-\frac{400}{40}$$

Divide 400 by 40 to get 10.

$$32-10$$

Subtract 10 from 32 to get 22.

$$22$$

Factor

$$2\times 11$$