Solve 2^5:2^2+sqrt{10^2-6^2}*2=

$$2 ^ { 5 } : 2 ^ { 2 } + \sqrt { 10 ^ { 2 } - 6 ^ { 2 } } \cdot 2 =$$

Evaluate

$$24$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 2 from 5 to get 3.

$$2^{3}+2\sqrt{10^{2}-6^{2}}$$

Calculate 2 to the power of 3 and get 8.

$$8+2\sqrt{10^{2}-6^{2}}$$

Calculate 10 to the power of 2 and get 100.

$$8+2\sqrt{100-6^{2}}$$

Calculate 6 to the power of 2 and get 36.

$$8+2\sqrt{100-36}$$

Subtract 36 from 100 to get 64.

$$8+2\sqrt{64}$$

Calculate the square root of 64 and get 8.

$$8+2\times 8$$

Multiply 2 and 8 to get 16.

$$8+16$$

Add 8 and 16 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$