Solve 2^{4}-2^3+2^2-2^1+2^0=

$$2 ^ { 4 } - 2 ^ { 3 } + 2 ^ { 2 } - 2 ^ { 1 } + 2 ^ { 0 } =$$

Evaluate

$$11$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$16-2^{3}+2^{2}-2^{1}+2^{0}$$

Calculate 2 to the power of 3 and get 8.

$$16-8+2^{2}-2^{1}+2^{0}$$

Subtract 8 from 16 to get 8.

$$8+2^{2}-2^{1}+2^{0}$$

Calculate 2 to the power of 2 and get 4.

$$8+4-2^{1}+2^{0}$$

Add 8 and 4 to get 12.

$$12-2^{1}+2^{0}$$

Calculate 2 to the power of 1 and get 2.

$$12-2+2^{0}$$

Subtract 2 from 12 to get 10.

$$10+2^{0}$$

Calculate 2 to the power of 0 and get 1.

$$10+1$$

Add 10 and 1 to get 11.

$$11$$

Factor

$$11$$