Solve 2^{4}*2^0+3^2-5^1*5^2=

$$2 ^ { 4 } \cdot 2 ^ { 0 } + 3 ^ { 2 } - 5 ^ { 1 } \cdot 5 ^ { 2 } =$$

Evaluate

$$-100$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 4 and 0 to get 4.

$$2^{4}+3^{2}-5^{1}\times 5^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2^{4}+3^{2}-5^{3}$$

Calculate 2 to the power of 4 and get 16.

$$16+3^{2}-5^{3}$$

Calculate 3 to the power of 2 and get 9.

$$16+9-5^{3}$$

Add 16 and 9 to get 25.

$$25-5^{3}$$

Calculate 5 to the power of 3 and get 125.

$$25-125$$

Subtract 125 from 25 to get -100.

$$-100$$

Factor

$$-100$$