Solve 2^4+[(6-15):(-4-5)-8]*2=

$$2 ^ { 4 } + [ ( 6 - 15 ) : ( - 4 - 5 ) - 8 ] \cdot 2 =$$

Evaluate

$$2$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$16+\left(\frac{6-15}{-4-5}-8\right)\times 2$$

Subtract 15 from 6 to get -9.

$$16+\left(\frac{-9}{-4-5}-8\right)\times 2$$

Subtract 5 from -4 to get -9.

$$16+\left(\frac{-9}{-9}-8\right)\times 2$$

Divide -9 by -9 to get 1.

$$16+\left(1-8\right)\times 2$$

Subtract 8 from 1 to get -7.

$$16-7\times 2$$

Multiply -7 and 2 to get -14.

$$16-14$$

Subtract 14 from 16 to get 2.

$$2$$

Factor

$$2$$