Solve 2^3*3:{[(3+5*2^2-2^3):3+1]*2-2^3}

$$2 ^ { 3 } \times 3 : \{ [ ( 3 + 5 \times 2 ^ { 2 } - 2 ^ { 3 } ) : 3 + 1 ] \times 2 - 2 ^ { 3 } \}$$

Evaluate

$$6$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{8\times 3}{\left(\frac{3+5\times 2^{2}-2^{3}}{3}+1\right)\times 2-2^{3}}$$

Multiply 8 and 3 to get 24.

$$\frac{24}{\left(\frac{3+5\times 2^{2}-2^{3}}{3}+1\right)\times 2-2^{3}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{24}{\left(\frac{3+5\times 4-2^{3}}{3}+1\right)\times 2-2^{3}}$$

Multiply 5 and 4 to get 20.

$$\frac{24}{\left(\frac{3+20-2^{3}}{3}+1\right)\times 2-2^{3}}$$

Add 3 and 20 to get 23.

$$\frac{24}{\left(\frac{23-2^{3}}{3}+1\right)\times 2-2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{24}{\left(\frac{23-8}{3}+1\right)\times 2-2^{3}}$$

Subtract 8 from 23 to get 15.

$$\frac{24}{\left(\frac{15}{3}+1\right)\times 2-2^{3}}$$

Divide 15 by 3 to get 5.

$$\frac{24}{\left(5+1\right)\times 2-2^{3}}$$

Add 5 and 1 to get 6.

$$\frac{24}{6\times 2-2^{3}}$$

Multiply 6 and 2 to get 12.

$$\frac{24}{12-2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{24}{12-8}$$

Subtract 8 from 12 to get 4.

$$\frac{24}{4}$$

Divide 24 by 4 to get 6.

$$6$$

Factor

$$2\times 3$$