Solve 2^{3}*2^2*2^-1+3^2*5^2

$$2 ^ { 3 } \cdot 2 ^ { 2 } \cdot 2 ^ { - 1 } + 3 ^ { 2 } \cdot 5 ^ { 2 }$$

Evaluate

$$241$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$2^{5}\times 2^{-1}+3^{2}\times 5^{2}$$

To multiply powers of the same base, add their exponents. Add 5 and -1 to get 4.

$$2^{4}+3^{2}\times 5^{2}$$

Calculate 2 to the power of 4 and get 16.

$$16+3^{2}\times 5^{2}$$

Calculate 3 to the power of 2 and get 9.

$$16+9\times 5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$16+9\times 25$$

Multiply 9 and 25 to get 225.

$$16+225$$

Add 16 and 225 to get 241.

$$241$$

Factor

$$241$$