Solve 2^3*(9-2)+12/4-|-5|

$$2 ^ { 3 } \cdot ( 9 - 2 ) + \frac { 12 } { 4 } - | - 5 |$$

Evaluate

$$54$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$8\left(9-2\right)+\frac{12}{4}-|-5|$$

Subtract 2 from 9 to get 7.

$$8\times 7+\frac{12}{4}-|-5|$$

Multiply 8 and 7 to get 56.

$$56+\frac{12}{4}-|-5|$$

Divide 12 by 4 to get 3.

$$56+3-|-5|$$

Add 56 and 3 to get 59.

$$59-|-5|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.

$$59-5$$

Subtract 5 from 59 to get 54.

$$54$$

Factor

$$2\times 3^{3}$$