Solve 2^3+3*(2017)^6+(-2)^2:1/2

$$2 ^ { 3 } + 3 \cdot ( 2017 ) ^ { 6 } + ( - 2 ) ^ { 2 } : \frac { 1 } { 2 }$$

Evaluate

$$202002453324967264723$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$8+3\times 2017^{6}+\frac{\left(-2\right)^{2}}{\frac{1}{2}}$$

Calculate 2017 to the power of 6 and get 67334151108322421569.

$$8+3\times 67334151108322421569+\frac{\left(-2\right)^{2}}{\frac{1}{2}}$$

Multiply 3 and 67334151108322421569 to get 202002453324967264707.

$$8+202002453324967264707+\frac{\left(-2\right)^{2}}{\frac{1}{2}}$$

Add 8 and 202002453324967264707 to get 202002453324967264715.

$$202002453324967264715+\frac{\left(-2\right)^{2}}{\frac{1}{2}}$$

Calculate -2 to the power of 2 and get 4.

$$202002453324967264715+\frac{4}{\frac{1}{2}}$$

Divide 4 by \frac{1}{2} by multiplying 4 by the reciprocal of \frac{1}{2}.

$$202002453324967264715+4\times 2$$

Multiply 4 and 2 to get 8.

$$202002453324967264715+8$$

Add 202002453324967264715 and 8 to get 202002453324967264723.

$$202002453324967264723$$

Factor

$$13\times 919\times 16908215729887609$$