Solve 2^2x=4

$$2 ^ { 2 x } = 4$$

Solve for x

$$x=1$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$2^{2x}=4$$

Take the logarithm of both sides of the equation.

$$\log(2^{2x})=\log(4)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$2x\log(2)=\log(4)$$

Divide both sides by \log(2).

$$2x=\frac{\log(4)}{\log(2)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$2x=\log_{2}\left(4\right)$$

Divide both sides by 2.

$$x=\frac{2}{2}$$

Solve for x (complex solution)

$$x=\frac{i\pi n_{1}}{\ln(2)}+1$$

$$n_{1}\in \mathrm{Z}$$