Solve 2^2-x^2=3-y

$$2 ^ { 2 } - x ^ { 2 } = 3 - y$$

Solve for y

$$y=x^{2}-1$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$4-x^{2}=3-y$$

Swap sides so that all variable terms are on the left hand side.

$$3-y=4-x^{2}$$

Subtract 3 from both sides.

$$-y=4-x^{2}-3$$

Subtract 3 from 4 to get 1.

$$-y=1-x^{2}$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{1-x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{1-x^{2}}{-1}$$

Divide -x^{2}+1 by -1.

$$y=x^{2}-1$$

Solve for x (complex solution)

$$x=-\sqrt{y+1}$$

$$x=\sqrt{y+1}$$

Solve for x

$$x=\sqrt{y+1}$$

$$x=-\sqrt{y+1}\text{, }y\geq -1$$