Solve 2^2-4*3*(2k-6)=0

$$2 ^ { 2 } - 4 \times 3 \times ( 2 k - 6 ) = 0$$

Solve for k

$$k = \frac{19}{6} = 3\frac{1}{6} \approx 3.166666667$$

Steps for Solving Linear Equation

Calculate 2 to the power of 2 and get 4.

$$4-4\times 3\left(2k-6\right)=0$$

Multiply 4 and 3 to get 12.

$$4-12\left(2k-6\right)=0$$

Use the distributive property to multiply -12 by 2k-6.

$$4-24k+72=0$$

Add 4 and 72 to get 76.

$$76-24k=0$$

Subtract 76 from both sides. Anything subtracted from zero gives its negation.

$$-24k=-76$$

Divide both sides by -24.

$$k=\frac{-76}{-24}$$

Reduce the fraction \frac{-76}{-24} to lowest terms by extracting and canceling out -4.

$$k=\frac{19}{6}$$