Solve 2^2*[3^2-(4+8)]+4div2

$$2 ^ { 2 } \cdot [ 3 ^ { 2 } - ( 4 + 8 ) ] + 4 \div 2$$

Evaluate

$$-10$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4\left(3^{2}-\left(4+8\right)\right)+\frac{4}{2}$$

Calculate 3 to the power of 2 and get 9.

$$4\left(9-\left(4+8\right)\right)+\frac{4}{2}$$

Add 4 and 8 to get 12.

$$4\left(9-12\right)+\frac{4}{2}$$

Subtract 12 from 9 to get -3.

$$4\left(-3\right)+\frac{4}{2}$$

Multiply 4 and -3 to get -12.

$$-12+\frac{4}{2}$$

Divide 4 by 2 to get 2.

$$-12+2$$

Add -12 and 2 to get -10.

$$-10$$

Factor

$$-10$$