Solve 2^2{-8/2+[2^2-(2^2)]+sqrt{81}}

$$2 ^ { 2 } \{ - \frac { 8 } { 2 } + [ 2 ^ { 2 } - ( 2 ^ { 2 } ) ] + \sqrt { 81 } \}$$

Evaluate

$$20$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4\left(-\frac{8}{2}+2^{2}-2^{2}+\sqrt{81}\right)$$

Divide 8 by 2 to get 4.

$$4\left(-4+2^{2}-2^{2}+\sqrt{81}\right)$$

Calculate 2 to the power of 2 and get 4.

$$4\left(-4+4-2^{2}+\sqrt{81}\right)$$

Calculate 2 to the power of 2 and get 4.

$$4\left(-4+4-4+\sqrt{81}\right)$$

Subtract 4 from 4 to get 0.

$$4\left(-4+0+\sqrt{81}\right)$$

Add -4 and 0 to get -4.

$$4\left(-4+\sqrt{81}\right)$$

Calculate the square root of 81 and get 9.

$$4\left(-4+9\right)$$

Add -4 and 9 to get 5.

$$4\times 5$$

Multiply 4 and 5 to get 20.

$$20$$

Factor

$$2^{2}\times 5$$