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2^{1,5x-3}=64
Use the rules of exponents and logarithms to solve the equation.
\log(2^{1,5x-3})=\log(64)
Take the logarithm of both sides of the equation.
\left(1,5x-3\right)\log(2)=\log(64)
The logarithm of a number raised to a power is the power times the logarithm of the number.
1,5x-3=\frac{\log(64)}{\log(2)}
Divide both sides by \log(2).
1,5x-3=\log_{2}\left(64\right)
By the change-of-base formula log(a)/log(b)=log(b,a).
1,5x=6-\left(-3\right)
Add 3 to both sides of the equation.
x=\frac{9}{1,5}
Divide both sides of the equation by 1,5, which is the same as multiplying both sides by the reciprocal of the fraction.