Solve 2[6-(8-3)-2(3-4)+1]

$$2 [ 6 - ( 8 - 3 ) - 2 ( 3 - 4 ) + 1 ]$$

Evaluate

$$8$$

Solution Steps

Subtract 3 from 8 to get 5.

$$2\left(6-5-2\left(3-4\right)+1\right)$$

Subtract 5 from 6 to get 1.

$$2\left(1-2\left(3-4\right)+1\right)$$

Subtract 4 from 3 to get -1.

$$2\left(1-2\left(-1\right)+1\right)$$

Multiply 2 and -1 to get -2.

$$2\left(1-\left(-2\right)+1\right)$$

The opposite of -2 is 2.

$$2\left(1+2+1\right)$$

Add 1 and 2 to get 3.

$$2\left(3+1\right)$$

Add 3 and 1 to get 4.

$$2\times 4$$

Multiply 2 and 4 to get 8.

$$8$$

Factor

$$2^{3}$$