Solve 2[4[7+4(5*3-9)]-3(40-8)]

$$2 [ 4 [ 7 + 4 ( 5 \cdot 3 - 9 ) ] - 3 ( 40 - 8 ) ]$$

Evaluate

$$56$$

Solution Steps

Multiply 5 and 3 to get 15.

$$2\left(4\left(7+4\left(15-9\right)\right)-3\left(40-8\right)\right)$$

Subtract 9 from 15 to get 6.

$$2\left(4\left(7+4\times 6\right)-3\left(40-8\right)\right)$$

Multiply 4 and 6 to get 24.

$$2\left(4\left(7+24\right)-3\left(40-8\right)\right)$$

Add 7 and 24 to get 31.

$$2\left(4\times 31-3\left(40-8\right)\right)$$

Multiply 4 and 31 to get 124.

$$2\left(124-3\left(40-8\right)\right)$$

Subtract 8 from 40 to get 32.

$$2\left(124-3\times 32\right)$$

Multiply 3 and 32 to get 96.

$$2\left(124-96\right)$$

Subtract 96 from 124 to get 28.

$$2\times 28$$

Multiply 2 and 28 to get 56.

$$56$$

Factor

$$2^{3}\times 7$$