Solve 2[3^3-(4*3+9)]-(3*6-15)+22-(8-6)

$$2 [ 3 ^ { 3 } - ( 4 \cdot 3 + 9 ) ] - ( 3 \cdot 6 - 15 ) + 22 - ( 8 - 6 )$$

Evaluate

$$29$$

Solution Steps

Calculate 3 to the power of 3 and get 27.

$$2\left(27-\left(4\times 3+9\right)\right)-\left(3\times 6-15\right)+22-\left(8-6\right)$$

Multiply 4 and 3 to get 12.

$$2\left(27-\left(12+9\right)\right)-\left(3\times 6-15\right)+22-\left(8-6\right)$$

Add 12 and 9 to get 21.

$$2\left(27-21\right)-\left(3\times 6-15\right)+22-\left(8-6\right)$$

Subtract 21 from 27 to get 6.

$$2\times 6-\left(3\times 6-15\right)+22-\left(8-6\right)$$

Multiply 2 and 6 to get 12.

$$12-\left(3\times 6-15\right)+22-\left(8-6\right)$$

Multiply 3 and 6 to get 18.

$$12-\left(18-15\right)+22-\left(8-6\right)$$

Subtract 15 from 18 to get 3.

$$12-3+22-\left(8-6\right)$$

Subtract 3 from 12 to get 9.

$$9+22-\left(8-6\right)$$

Add 9 and 22 to get 31.

$$31-\left(8-6\right)$$

Subtract 6 from 8 to get 2.

$$31-2$$

Subtract 2 from 31 to get 29.

$$29$$

Factor

$$29$$