Solve 2=e^4*6^2/2+C

$$2 = e ^ { 4 } \cdot \frac { 6 ^ { 2 } } { 2 } + C$$

Solve for C

$$C=-18e^{4}+2\approx -980.766700597$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$4=e^{4}\times 6^{2}+2C$$

Calculate 6 to the power of 2 and get 36.

$$4=e^{4}\times 36+2C$$

Swap sides so that all variable terms are on the left hand side.

$$e^{4}\times 36+2C=4$$

Subtract e^{4}\times 36 from both sides.

$$2C=4-e^{4}\times 36$$

Multiply -1 and 36 to get -36.

$$2C=4-36e^{4}$$

The equation is in standard form.

$$2C=-36e^{4}+4$$

Divide both sides by 2.

$$\frac{2C}{2}=\frac{-36e^{4}+4}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$C=\frac{-36e^{4}+4}{2}$$

Divide 4-36e^{4} by 2.

$$C=-18e^{4}+2$$