Solve 2=-8/3(-8)+1

$$2 = - \frac{ 8 }{ 3 } (-8)+1$$

Verify

Solution Steps

Express -\frac{8}{3}\left(-8\right) as a single fraction.

$$2=\frac{-8\left(-8\right)}{3}+1$$

Multiply -8 and -8 to get 64.

$$2=\frac{64}{3}+1$$

Convert 1 to fraction \frac{3}{3}.

$$2=\frac{64}{3}+\frac{3}{3}$$

Since \frac{64}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$2=\frac{64+3}{3}$$

Add 64 and 3 to get 67.

$$2=\frac{67}{3}$$

Convert 2 to fraction \frac{6}{3}.

$$\frac{6}{3}=\frac{67}{3}$$

Compare \frac{6}{3} and \frac{67}{3}.

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