Solve 2+9*2/5*9/8*5/10

$$2 + 9 \times \frac { 2 } { 5 } \times \frac { 9 } { 8 } \times \frac { 5 } { 10 }$$

Evaluate

$$\frac{161}{40}=4.025$$

Solution Steps

Express 9\times \frac{2}{5} as a single fraction.

$$2+\frac{9\times 2}{5}\times \frac{9}{8}\times \frac{5}{10}$$

Multiply 9 and 2 to get 18.

$$2+\frac{18}{5}\times \frac{9}{8}\times \frac{5}{10}$$

Multiply \frac{18}{5} times \frac{9}{8} by multiplying numerator times numerator and denominator times denominator.

$$2+\frac{18\times 9}{5\times 8}\times \frac{5}{10}$$

Do the multiplications in the fraction \frac{18\times 9}{5\times 8}.

$$2+\frac{162}{40}\times \frac{5}{10}$$

Reduce the fraction \frac{162}{40} to lowest terms by extracting and canceling out 2.

$$2+\frac{81}{20}\times \frac{5}{10}$$

Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$2+\frac{81}{20}\times \frac{1}{2}$$

Multiply \frac{81}{20} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$2+\frac{81\times 1}{20\times 2}$$

Do the multiplications in the fraction \frac{81\times 1}{20\times 2}.

$$2+\frac{81}{40}$$

Convert 2 to fraction \frac{80}{40}.

$$\frac{80}{40}+\frac{81}{40}$$

Since \frac{80}{40} and \frac{81}{40} have the same denominator, add them by adding their numerators.

$$\frac{80+81}{40}$$

Add 80 and 81 to get 161.

$$\frac{161}{40}$$

Factor

$$\frac{7 \cdot 23}{2 ^ {3} \cdot 5} = 4\frac{1}{40} = 4.025$$