Solve 2+(-51/4)-(-21/3)

$$2 + ( - 5 \frac { 1 } { 4 } ) - ( - 2 \frac { 1 } { 3 } )$$

Evaluate

$$-\frac{11}{12}\approx -0.916666667$$

Solution Steps

Multiply 5 and 4 to get 20.

$$2-\frac{20+1}{4}-\left(-\frac{2\times 3+1}{3}\right)$$

Add 20 and 1 to get 21.

$$2-\frac{21}{4}-\left(-\frac{2\times 3+1}{3}\right)$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{8}{4}-\frac{21}{4}-\left(-\frac{2\times 3+1}{3}\right)$$

Since \frac{8}{4} and \frac{21}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-21}{4}-\left(-\frac{2\times 3+1}{3}\right)$$

Subtract 21 from 8 to get -13.

$$-\frac{13}{4}-\left(-\frac{2\times 3+1}{3}\right)$$

Multiply 2 and 3 to get 6.

$$-\frac{13}{4}-\left(-\frac{6+1}{3}\right)$$

Add 6 and 1 to get 7.

$$-\frac{13}{4}-\left(-\frac{7}{3}\right)$$

The opposite of -\frac{7}{3} is \frac{7}{3}.

$$-\frac{13}{4}+\frac{7}{3}$$

Least common multiple of 4 and 3 is 12. Convert -\frac{13}{4} and \frac{7}{3} to fractions with denominator 12.

$$-\frac{39}{12}+\frac{28}{12}$$

Since -\frac{39}{12} and \frac{28}{12} have the same denominator, add them by adding their numerators.

$$\frac{-39+28}{12}$$

Add -39 and 28 to get -11.

$$-\frac{11}{12}$$

Factor

$$-\frac{11}{12} = -0.9166666666666666$$