Solve 2+(-sqrt{3})^2-1+(1/6)^-1

$$2 + ( - \sqrt { 3 } ) ^ { 2 } - 1 + ( \frac { 1 } { 6 } ) ^ { - 1 }$$

Evaluate

$$10$$

Solution Steps

Calculate -\sqrt{3} to the power of 2 and get \left(\sqrt{3}\right)^{2}.

$$2+\left(\sqrt{3}\right)^{2}-1+\left(\frac{1}{6}\right)^{-1}$$

Subtract 1 from 2 to get 1.

$$1+\left(\sqrt{3}\right)^{2}+\left(\frac{1}{6}\right)^{-1}$$

The square of \sqrt{3} is 3.

$$1+3+\left(\frac{1}{6}\right)^{-1}$$

Add 1 and 3 to get 4.

$$4+\left(\frac{1}{6}\right)^{-1}$$

Calculate \frac{1}{6} to the power of -1 and get 6.

$$4+6$$

Add 4 and 6 to get 10.

$$10$$

Factor

$$2\times 5$$