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2+\sqrt{3}-\frac{4\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{4}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
2+\sqrt{3}-\frac{4\sqrt{3}}{3}
The square of \sqrt{3} is 3.
2-\frac{1}{3}\sqrt{3}
Combine \sqrt{3} and -\frac{4\sqrt{3}}{3} to get -\frac{1}{3}\sqrt{3}.