Solve 2+2/x+1)*(3-6/x+2)*(1+1/x)=

$$2 + \frac { 2 } { x + 1 } ) \cdot ( 3 - \frac { 6 } { x + 2 } ) \cdot ( 1 + \frac { 1 } { x } ) =$$

Evaluate

$$\frac{2\left(x+2\right)}{x+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{x+1}{x+1}.

$$\frac{2\left(x+1\right)}{x+1}+\frac{2}{x+1}$$

Since \frac{2\left(x+1\right)}{x+1} and \frac{2}{x+1} have the same denominator, add them by adding their numerators.

$$\frac{2\left(x+1\right)+2}{x+1}$$

Do the multiplications in 2\left(x+1\right)+2.

$$\frac{2x+2+2}{x+1}$$

Combine like terms in 2x+2+2.

$$\frac{2x+4}{x+1}$$

Factor

$$\frac{2\left(x+2\right)}{x+1}$$