Solve 2+{5*[(6-4:2)^2-15]^4-3}^3

$$2 + \{ 5 \cdot [ ( 6 - 4 : 2 ) ^ { 2 } - 15 ] ^ { 4 } - 3 \} ^ { 3 }$$

Evaluate

$$10$$

Solution Steps

Divide 4 by 2 to get 2.

$$2+\left(5\left(\left(6-2\right)^{2}-15\right)^{4}-3\right)^{3}$$

Subtract 2 from 6 to get 4.

$$2+\left(5\left(4^{2}-15\right)^{4}-3\right)^{3}$$

Calculate 4 to the power of 2 and get 16.

$$2+\left(5\left(16-15\right)^{4}-3\right)^{3}$$

Subtract 15 from 16 to get 1.

$$2+\left(5\times 1^{4}-3\right)^{3}$$

Calculate 1 to the power of 4 and get 1.

$$2+\left(5\times 1-3\right)^{3}$$

Multiply 5 and 1 to get 5.

$$2+\left(5-3\right)^{3}$$

Subtract 3 from 5 to get 2.

$$2+2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$2+8$$

Add 2 and 8 to get 10.

$$10$$

Factor

$$2\times 5$$