Solve 2+[(-1)^-1]-2tan30^circ-(2-299)^2

$$2 + [ ( - 1 ) ^ { - 1 } ] - 2 \tan 30 ^ { \circ } - ( 2 - 299 ) ^ { 2 }$$

Evaluate

$$-\frac{2\sqrt{3}}{3}-88208\approx -88209.154700538$$

Short Solution Steps

Calculate -1 to the power of -1 and get -1.

$$2-1-2\tan(30)-\left(2-299\right)^{2}$$

Subtract 1 from 2 to get 1.

$$1-2\tan(30)-\left(2-299\right)^{2}$$

Get the value of \tan(30) from trigonometric values table.

$$1-2\times \frac{\sqrt{3}}{3}-\left(2-299\right)^{2}$$

Express 2\times \frac{\sqrt{3}}{3} as a single fraction.

$$1-\frac{2\sqrt{3}}{3}-\left(2-299\right)^{2}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{3}{3}.

$$\frac{3}{3}-\frac{2\sqrt{3}}{3}-\left(2-299\right)^{2}$$

Since \frac{3}{3} and \frac{2\sqrt{3}}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-2\sqrt{3}}{3}-\left(2-299\right)^{2}$$

Subtract 299 from 2 to get -297.

$$\frac{3-2\sqrt{3}}{3}-\left(-297\right)^{2}$$

Calculate -297 to the power of 2 and get 88209.

$$\frac{3-2\sqrt{3}}{3}-88209$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 88209 times \frac{3}{3}.

$$\frac{3-2\sqrt{3}}{3}-\frac{88209\times 3}{3}$$

Since \frac{3-2\sqrt{3}}{3} and \frac{88209\times 3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-2\sqrt{3}-88209\times 3}{3}$$

Do the multiplications in 3-2\sqrt{3}-88209\times 3.

$$\frac{3-2\sqrt{3}-264627}{3}$$

Do the calculations in 3-2\sqrt{3}-264627.

$$\frac{-264624-2\sqrt{3}}{3}$$